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This is my code:
user_string = input("What's your word? ") user_num = input("What's your number? ") try: our_num - int(user_num) except: our_num = float(user_num) if not "." in user_num: print(user_string[our_num]) else: ratio = round(len(user_string) * our_num) print(user_string[ratio]) #When I run it I get the following syntax error message: File "percent_letter,py", line 9 if not '.' in user num: SyntaxError: invalid syntax
If changed the "." to '.' and get the same error. I've also copied and pasted code from other posts and get the same error.
Please help!! :(
Chris FreemanTreehouse Moderator 68,064 Points
user_num is a string,
if '.' not in user_num: and
if not '.' in user_num: both work.
There appears to be a typo: "-" where a "=" should be:
try: our_num = int(user_num) # <-- replaced - with = except: our_num = float(user_num)