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georgebadoles
4,173 PointsIOS Development : Functions challenge test 1
This is my solution : float addTwo(float a, float b); float addTwo(float a, float b) { float a = 13.14; float b = 23.23; float result = a + b; printf("%f", result); return result; }
4 Answers
Stone Preston
42,016 PointsThis is my solution : float addTwo(float a, float b) { float a = 12.21; float b = 12.212; float result = a + b; retun result; }
remember you dont need to declare any local variables in the body of the function. Use the parameters a and b you defined in the function header. you also misspelled return
float addTwo(float a, float b) {
float result = a + b;
return result;
}
Stone Preston
42,016 Pointsall you need to do is implement the function. you do not need to declare any variables, you dont need a function prototype. all you need is the function implementation. here is a shell of what your function should look like:
returnType functionName(dataType parameterOne, dataType parameterTwo) {
return something;
}
the challenge tells you it needs to be named add two, it needs to take two arguments (these are your parameters). these arguments need to be of the type float. then you need to return the sum of the parameters. since you are returning the sum of 2 floats your return type needs to be a float.
note that I called the variables inside the parenthesis parameters. When implementing a function, the variables you put inside the ( ) are known as parameters. When calling a function, they are arguments.
georgebadoles
4,173 PointsHi Stone,
Thank you for you reply.
This is my solution : float addTwo(float a, float b) { float a = 12.21; float b = 12.212; float result = a + b; retun result; }
But still the return error is: Make sure you've defined the return type and both paramter types as 'float' and that you are returning the sum of the arguments as a result.
georgebadoles
4,173 PointsOh my fault. Thank you for your help Stone.