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PHP Object-Oriented PHP Basics (Retired) Inheritance, Interfaces, and Exceptions Managing Exceptions

michaelmugo
michaelmugo
3,971 Points
Posted by michaelmugo
michaelmugo
3,971 Points

Is $e an object created from the Exception class?

If it is, how come it is not declared as:

$e = new Exception();

1 Answer

Shawn Gregory
PLUS
Shawn Gregory
Courses Plus Student 40,672 Points
Shawn Gregory
Shawn Gregory
Courses Plus Student 40,672 Points

Michaelmugo,

Here's PHP's manual on exceptions which explains things a little more thoroughly. The $e instance is created when you reach the catch block:

You are actually instantiating the Exception class when you throw the exception:

if($a != $b) {
   throw new Exception("Variables are not equal");
}
catch(Exception $e){
   $error = $e->getMessage();
}

Once you get to the catch block you are creating $e and identifying it as class type Exception. You can then use $e like you would any other way you would use classes. Also, you can also have multiple catch blocks per situation, create your own exception class, and use the keyword 'finally' when dealing with exceptions,. I would click the link and read the documentation for more information. Hope this helps.

Cheers!