Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

iOS Swift Functions and Optionals Optionals Exercise: isDivisible function

is it right to do it like this ?

Hello i tried to write the exercise that Mr.Amit asked to do ,and i wrote it as this :

func numdv (#numdiv : Int , #number : Int) -> Bool? {
    var numbers = (1...100)
    for myQ in numbers {
        if numdiv % number == 0 {
            return true
        } else {
            return nil
        }
    }

    if let Answer = numdv(numdiv: 9, number: 4){
        println("Divisible")
    } else {
        println("not Divisible")
    }
}

is it right ? Now i think it's right way to write it like this but i don't Know i still have mistakes !

Richard Lu
Richard Lu
20,185 Points

I've fixed up the snippet of code for readability. :)

5 Answers

Richard Lu
Richard Lu
20,185 Points

Hey Nour,

Here's the solution which also guides you through how someone would approach this problem.

// the function takes 2 int parameters
func areNumsDivisible(num1 num1: Int, num2: Int) -> Bool? /* returns an optional bool */ {  
    // this part, the function is figuring out if the first parameter is divisible by the second
    // if a number is divisible by another, then it should have no remainder (hence the modulus operator)
    if num1 % num2 == 0 {
        // if the number is divisible it returns a true
        return true
    } else {
        // otherwise it returns a nil
        return nil
    }
}

// calling the function with 2 numbers 
let x = areNumsDivisible(num1: 1, num2: 1) 

// printing out whether “Divisible” or “Not Divisible”
if x != nil {
    print("Divisible")
} else {
    print("Not divisible")
}

Hope I've helped. Happy Coding! :)

So the way that you used is the only way to write this code ?

Richard Lu
Richard Lu
20,185 Points

Hey Nour,

Not exactly, there are other methods of approaching this problem, but they all follow the same guidelines. Keep in mind that sometimes there are multiple solutions to a problem. Here's another way you can do it (slightly a bit more advanced).

func areNumsDivisible(num1 num1: Int, num2: Int) -> Bool? {  
    return num1 % num2 == 0 ? true : nil
}

print(areNumsDivisible(num1: 1, num2: 1) != nil ? "Divisible" : "Not Divisible")

aha thats my point how to learn those several ways to approaching problems ? how to get this level of learning ?

Richard Lu
Richard Lu
20,185 Points

With lots of practice! You'll eventually notice that some things can be placed together like a puzzle.

Thank you Richard Lu ,

Nour. . .

Richard Lu
Richard Lu
20,185 Points

My pleasure Nour! I'm always looking to help :)

I think there's some additional clarity available here when considering the unwrapping of an optional value. Testing for nil works in this instance, but the purpose of the optional, and the if let construct, is lost this way.

I recalled writing a response a while ago for another similar question so thought I'd share that here as it discusses the isDivisible function, the purpose of optioanl unwrapping and a few other questions that were raised. I think it is relevant to this question, so thought I'd post it here

Hope it adds something for you.

Steve.