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Kathleen Rauh
1,785 PointsIs my function not defined properly?
I get Bummer! Where's members()?
# You can check for dictionary membership using the
# "key in dict" syntax from lists.
### Example
# my_dict = {'apples': 1, 'bananas': 2, 'coconuts': 3}
# my_list = ['apples', 'coconuts', 'grapes', 'strawberries']
# members(my_dict, my_list) => 2
def members(my_dict, my_list):
for key in my_dict:
if key in my_list:
count += 1
return count
3 Answers
Chase Marchione
155,055 PointsHi Kathleen,
You'll want to make sure that your count starts at 0, so that the first time a key is found the count becomes 1, and that the next time a key is found it'll go up to 2, and so on.
The way I completed the task: I had the for loop check if the key is in the list. Then, within that for loop, I had the if statement check if that key is among the dictionary's keys.
def members(my_dict, my_list):
count = 0
for key in my_list:
if key in my_dict.keys():
count += 1
return count
Hope this helps!
Kathleen Rauh
1,785 PointsStill struggling. After making changes, and "earning" several other bummers, I'm again getting the "Where's members()" bummer.
Here's the code: count = 0 def members(my_dict, my_list): for key in my_list: if key in my_dict.keys(): count += 1 return count
Chase Marchione
155,055 PointsMake sure that your count initialization statement comes after the function header: you want to initialize count within the function (but not within the for loop.)
Andrea Campos
4,743 PointsHey Kathleen! I'm stuck with the same problem. I get "Where's members()?" How did you get through this? Thank you! A.