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Python Python Collections (2016, retired 2019) Slices sillyCase

Posted by newpal
newpal
1,717 Points

Is there a different approach to solving this challenge?

def sillycase(string): string1 = sillycase[:len(string)//2].lower() string2 = sillycase[len(string)//2:].upper() return string1 + string2

sillycase.py 
def sillycase(string):
    string1 = sillycase[:len(string)//2].lower()
    string2 = sillycase[len(string)//2:].upper()
    return string1 + string2
newpal
newpal
1,717 Points

Sorry, I meant the following code:

def sillycase(string):
    string1 = string[:len(string)//2].lower()
    string2 = string[len(string)//2:].upper()
    return string1 + string2

[MOD: added formatting -cf]

2 Answers

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

You seem to have the "classic" solution there. You could eliminate the temporary string variables and add one to prevent calculating the size twice, but that's just minor implementation differences, not really a change in approach:

def sillycase(string):
    half = len(string) // 2
    return string[:half].lower() + string[half:].upper()
newpal
newpal
1,717 Points
newpal
newpal
1,717 Points

Thanks Steven!