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Python Dates and Times in Python Dates and Times Timedelta Minute

Trace Harris
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Trace Harris
Python Web Development Techdegree Graduate 22,065 Points

Is there an issue with my logic

So my understanding is that I am supposed to get the total seconds for each, then subtract the 1st from the second then floor divide by 60 and return that value, or should I subtract datetime1 from datetime2 then get the timedelta.total_seconds() and divide by 60 and return the resulting value?

minutes.py
import datetime

def minutes(dt_one, dt_two):
    seconds_one = dt_one.timedelta.total_seconds() 
    seconds_two = dt_two.timedelta.total_seconds()
    total_sec =seconds_one - seconds_two 
    t1 = total_sec // 60
    return t1

1 Answer

Steven Parker
Steven Parker
210,130 Points

You're on the right track with your alternate suggestion. You get the total seconds from the difference between the times, which will be a timedelta. Here's a few other hints:

  • you'll need to subtract the times first
  • the function "total_seconds" is used on a timedelta but does not have that word in it's name
  • the challenge wants "the number of minutes, rounded", not truncated ("floor"ed)