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JavaScript

Is there anyone who can help me with the JavaScript challenges?

Is there anyone who can help me with the JavaScript challenges? I am getting the first and/or second steps right but not able to get the whole challenges correct...

Is there anyone who can help me with these?

5 Answers

Yes Brooke ,

I Already Answer Your Question on The Old Post ;)

https://teamtreehouse.com/community/what-is-the-last-step

Cheers!

Edit


I'm Really Sorry For Misunderstanding. Your Code is Almost Right. The Instruction may sound a bit confusing. Just Create New Variable Name Echo That Call The Return Value Function

var echo = returnValue("My name is Brooke");

The Full Code Looks Like This

function returnValue(brooke){
   return brooke;
}
var echo = returnValue("My name is Brooke");

Thanks

This is a different one I am getting wrong lol.

Challenge Task 2 of 2 After your newly created returnValue function, create a new variable named echo. Set the value of echo to be the results from calling the returnValue function. When you call the returnValue function, make sure to pass in any string you'd like for the parameter. 

function returnValue (x) {
return x; } var echo();

I am not getting this one right either :(

function returnValue(brooke){
   return brooke;
}
var echo = returnValue("My name is Brooke");

I'm Really Sorry For Misunderstanding. Your Code is Almost Right. The Instruction may sound a bit confusing. Just Create New Variable Name Echo That Call The Return Value Function

var echo = returnValue("My name is Brooke");

Challenge Task 1 of 2 Create a new function named max which accepts two numbers as arguments (you can name the arguments, whatever you would like). The function should return the larger of the two numbers.

HINT: You'll need to use a conditional statement to test the 2 parameters to see which is the larger of the two.

This is my code:

function max(x, y) { if(X > y); { return x; } else { return y; } }

function max(x , y ){
 if(x > y ) {
   return x;
 }
 return y;
}

For Challenge 2 ,

In case you ask me :)

function max(x , y ){
 if(x > y ) {
   return x;
 }
 return y;
}
alert(max(5,6));

Thank you SO SO much!

You're Welcome :)