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Start your free trialJannik Spiessens
13,229 Pointsis this a better or worse way to make the FizzBuzz generator?
for i in 1...20 {
if i % 3 == 0 {
print("Fizz")
}
if i % 5 == 0 {
print("Buzz")
}
if i % 5 != 0 && i % 3 != 0 {
print(i)
}
println()
}
I am using the print() function in stead of the println() function to make the "Buzz" stand behind the "Fizz".
2 Answers
Steve Hunter
57,712 PointsMy code looks like:
func fizzbuzz(#number: Int){
if number % 3 == 0 && number % 5 == 0 {
println("FizzBuzz")
} else if number % 5 == 0 {
println("Buzz")
} else if number % 3 == 0 {
println("Fizz")
} else {
println("No fizzing, buzzing, or fizzbuzzing for you!")
}
}
I then tested it with a loop:
for var i = 0; i < 50; i++ {
fizzbuzz(number: i)
}
I hope that helps.
Steve.
Phil Hanson
764 PointsMay I also add the one addition:
for i in 1...20 {
if (i % 3 == 0) && (i % 5 == 0) {
print("\(i) - FizzBuzz")
} else if (i % 3 == 0) {
print("\(i) - Fizz")
} else if (i % 5 == 0) {
print("\(i) - Buzz")
} else {
print("\(i) - Null")
}
}
This lets you see each number for a bit more clarity.