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JavaScript JavaScript Foundations Functions Return Values

Is this a bug?

I put the following code:

function arrayCounter (array) { if(typeOf array === "undefined"){ return 0; } return array.length; }

and is showing the message: "Bummer! You're missing a function called arrayCounter!" ah?! :)

2 Answers

Richard Duncan
Richard Duncan
5,568 Points

Yeah you're close though. The typeof method is all lowercase and you're missing the else condition from your if statement.

I've posted a solution below but please take note of the structure of the if statement in the body of the function.

function arrayCounter (array) { 
  if (typeof array === "undefined") { 
    return 0; 
  } else {
    return array.length;

This is the same as saying if array is identical to undefined then return 0. If the value of array is not identical to undefined (i.e. everything else) then return array.length.

Yes, I figured that I had a mistake on "typeof", thanks! ;)

But was missing another important point - inside the IF statement we also need to input : typeof array ==="undefined" || typeof array ==="string" || typeof array ==="number"

Thanks! :)

Richard Duncan
Richard Duncan
5,568 Points

Yep and well done for figuring it out! If you found it useful you could mark as correct so as to help someone in future :) glad I could assist!