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JavaScript JavaScript Basics (Retired) Creating Reusable Code with Functions Random Number Challenge, Part II Solution

Ivan Kusakovic
Ivan Kusakovic
12,197 Points
Posted by Ivan Kusakovic
Ivan Kusakovic
12,197 Points

Is this also correct with NaN?

function getRandom(a,b){
  if (isNaN(a||b)){ 
    throw new Error("there is smth what's not a number");
  }else{
      return Math.floor(Math.random() * (a - b +1 ) +b);
  }
}

alert(getRandom(100,2));
alert(getRandom(6,0));
alert(getRandom(1030,255));
alert(getRandom("ivan",222));
alert(getRandom(100,50));

This (isNaN(a||b)) works also.

6 Answers

lakindujayathilaka
lakindujayathilaka
15,244 Points

Hello :) I messed around with your code a little bit and i came up with this

function getRandomNumber(min,max){
  if(isNaN(min) || isNaN(max)){
    throw new Error("Please enter numbers only!");
  }else {
    return Math.floor(Math.random() * (min - max) + 1) + max; 
  }
}

You can call that function and check..it works fine the function u wrote is a bit confusing..this is more simple yet performs the same task as your function thanks

Brian Mendez
Brian Mendez
7,734 Points
Brian Mendez
Brian Mendez
7,734 Points

I can see how you thought that worked. Either way, good thinking though Ivan.

Ivan Kusakovic
Ivan Kusakovic
12,197 Points
Ivan Kusakovic
Ivan Kusakovic
12,197 Points

Why write longer if you can shorter? I can't see you made much different with messing with my code. Messing :)

 IsNaN(a||b)

is quite understandable so I recommend this :)

lakindujayathilaka
lakindujayathilaka
15,244 Points

it doesn't work bro you have to give the full conditions on either side

Ivan Kusakovic
Ivan Kusakovic
12,197 Points
Ivan Kusakovic
Ivan Kusakovic
12,197 Points

It works. I tried and works. It actually compare if is not a number a or b ... isNaN(a||b) compare if isNan(true) a||b is true if either of a or b is true so that works.

Try and you'll see it ;)

Casey Ydenberg
Casey Ydenberg
15,622 Points
Casey Ydenberg
Casey Ydenberg
15,622 Points 
isNaN(1||'casey') // returns false
isNaN('casey'||1) // returns true

Remember that b || c returns b is b is truthy and c if b is falsey; so in your code, isNaN is evaluating either the first argument or the second but not both of them.

Ivan Kusakovic
Ivan Kusakovic
12,197 Points
Ivan Kusakovic
Ivan Kusakovic
12,197 Points

Ah, yeah. Sorry, I was little bit confused because I typed as example right choice :D

Thanks Casey :)