Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python

Stivan Radev
Stivan Radev
1,475 Points
Posted by Stivan Radev
Stivan Radev
1,475 Points

Is this an efficient way of doing this challenge?

Great! Now use .remove() and/or del to remove the string, the boolean, and the list from inside of messy_list. When you're done, messy_list should have only integers in it.

If this is not an efficient way of doing this, what else could 've done?

messy_list = ["a", 2, 3, 1, False, [1, 2, 3]]

popit = messy_list.pop(3)
messy_list.insert(0, popit)

messy_list.remove('a')
messy_list.remove(False)
messy_list.remove([1, 2, 3])

Also, I'm pretty new and I don't think that I know any complex algorithms. Is this good for now? I mean the code did work, but I'm just curious if there was another approach to this.

1 Answer

Steven Parker
Steven Parker
231,122 Points
Steven Parker
Steven Parker
231,122 Points

Making it work is the important objective at this point. As you progress, you will continue to add skills to your "toolkit" and will be able to choose among them for the most efficient way to approach each task.

One thing you might have done was hinted at in task 1. You could do it on one line without creating a new variable:

messy_list.insert(0, messy_list.pop(3))
Stivan Radev
Stivan Radev
1,475 Points
Stivan Radev
Stivan Radev
1,475 Points

Ok cool, thank you so much for your help and guidance :)