Conner WilliamsPro Student 2,865 Points
Is this anywhere near being correct?
after taking some time to think about this one, I feel I might be getting somewhere. Still completely unsure though.
def loopy(items): # Code goes here for item in items: print(item) if index(0) == 'a': continue else: print(current number)
Steven Parker163,370 Points
You won't need the "else" or the second "print" (plus that phrase "current number" doesn't mean anything to the program).
Then you need to re-order your lines so the test is done before the print, and indent the test more to put it inside the loop.
Finally, instead of "index(0)" you need "item" to get the first letter of the item.
I'll bet you can get it now without an explicit code spoiler.
Haydar Al-Rikabi5,964 Points
To demonstrate Steven's reply, see the following code:
def loopy(items): for item in items: if item == 'a': # Use square brackets  rather than parentheses () continue print(item) # If the condition above fails, then this line is executed