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Android Build a Simple Android App (2014) Basic Android Programming Using the Random Class

Posted by nandish bs
nandish bs
361 Points

is this correct?

thanks in advance

RandomTest.java 
string intAsString = "";
Random randomGenerator = new Random();
 factlabel.setText(intAsString);
int randomNumber = randomGenerator.nextInt(10);
intAsString=randomNumber+"";

2 Answers

Steve Hunter
Steve Hunter
57,712 Points

Right, so you start this challenge with:

Random randomGenerator;

First you have to use the constructor to instantiate a new instance. You can do that by modifying the provided line, like you have, or just add:

randomGenerator = new Random();

Either works fine. Next, you need to create a new variable and assign a value to it using a method of the RandomGenerator class:

int randomNumber = randomGenerator.nextInt();

You then need to amend that to add bounds to the value of the random number generated:

int randomNumber = randomGenerator.nextInt(10);

Lastly you need to moosh a new string variable to hold the generated number:

String intAsString = randomNumber + "";

You're pretty much there - just no labels involved in the challenge. Hope that helps!

Steve.

nandish bs
nandish bs
361 Points
nandish bs
nandish bs
361 Points

thanks bro:)

Steve Hunter
Steve Hunter
57,712 Points

No problem! ;-)

Steve.