isDivisible

Question

Cant seem to get the code right to let me know whether a dividend is not divisible by the divisor ?

Answer 1 · 2015-12-06T02:47:30Z

December 6, 2015 2:47am

Hello Raymond,

This one had me stumped to until I reviewed Swifts comparison operators Equal to (a == b) Not equal to (a != b) Greater than (a > b) Less than (a < b) Greater than or equal to (a >= b) Less than or equal to (a <= b)

so its the exact same code as "isDivisible" except you change the comparison operator from "==" to "!=" and change the function name to "isNotDivisible" and your all set.

func isNotDivisible(#dividend: Int, #divisor: Int) -> Bool { if dividend % divisor != 0 { return true } else { return false } }

Hope this helps and if it does I would love to get best answer for the thread. Just finished the coursework and getting pretty close with my three apps but having a hard time getting points in the forum.

Good luck and happy learning

Justin

Answer 2 · 2015-12-06T21:12:10Z

December 6, 2015 9:12pm

Expanding on Justin's answer, you can reduce the amount of lines in your function, given that the evaluation of dividend % divisor != 0 will return a boolean value, into a single line, something like this:

func isNotDivisible(dividend:Int, divisor:Int) -> Bool {
    return dividend % divisor != 0
}

isNotDivisible(4, divisor: 2) // false
isNotDivisible(5, divisor: 2) // true

You can also see this problem this way, first find out if the remainder is zero, the negate that answer, so, something like this:

func isNotDivisible(dividend:Int, divisor:Int) -> Bool {
    return !isDivisible(dividend, divisor: divisor)
}

func isDivisible(dividend:Int, divisor:Int) -> Bool {
    return dividend % divisor == 0
}

Will yield the same result

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Raymond Espinoza

Raymond Espinoza

isDivisible

2 Answers

Justin Reed

Justin Reed

Leo Picado

Leo Picado