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Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and a supportive community. Start your free trial today. # isDivisible function works in Playground but not is code challenge

Here is my code: func isDivisible (dividend: Int, divisor: Int) -> Bool? { if dividend % divisor == 0 { return true } else { return false } }

func isNotDivisible (dividend: Int, divisor: Int) -> Bool? { if dividend % divisor != 0 { return true } else { return false } }

if let answer = isDivisible(15, divisor: 3) { print("Divisible", terminator: "") } else { print("Not Divisible", terminator: "") }

if let result = isNotDivisible(15, divisor: 3) { print("Not Divisible", terminator: "") } else { print("Divisible", terminator: "") }

divisible.swift
```func isDivisible (dividend: Int, divisor: Int) -> Bool? {
if dividend % divisor == 0 {
return true
} else {
return nil
}
}

func isNotDivisible (dividend: Int, divisor: Int) -> Bool? {
if dividend % divisor != 0 {
return true
} else {
return nil
}
}

if let divisible = isDivisible(15, 3) {
print("Divisible", terminator: "")
} else {
print("Not Divisible", terminator: "")
}

if let result = isNotDivisible(15, 3) {
print("Not Divisible", terminator: "")
} else {
print("Divisible", terminator: "")
}
```

The question is looking for your method to return a Boolean, not an Optional - so if you amend your lines `return nil` to `return false` that may assist.

Also, you've duplicated pretty much the whole method. The two methods are a character, or so, different. How about calling `isDivisible` from inside `isNotDivisible` and negating the returned value?

```func isDivisible(#dividend: Int, #divisor: Int) -> Bool {
if dividend % divisor == 0 {
return true
} else {
return false
}
}

func isNotDivisible(#dividend: Int, #divisor: Int) -> Bool {
return !isDivisible(dividend: dividend, divisor: divisor)
}
```

That's more DRY.

Hope that makes sense.

Steve.

The question asks for a method that returns a boolean depending whether the divisor and dividend are not divisible. How you do that is wholly up to you - there's no requirement to repeat code.

I think the Treehouse lessons make a strong point of refactoring to avoid repetition but it isn't always easy to see how to achieve it. Thankfully, this challenge will pass with both ways of achieving the result so the duplicated methd is fine, and it is only a few lines of code.

Steve.