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Chadrak Fertil
2,221 PointsIsn't this right?
Why wont this work?
console.log(2);
console.log(4);
console.log(6);
console.log(8);
console.log(10);
console.log(12);
console.log(14);
console.log(16);
console.log(18);
console.log(20);
console.log(22);
console.log(24);
for (var i = 0; i < 25; i++2;) {
console.log(i);
}
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>JavaScript Loops</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>
3 Answers
Darryl Mah
5,492 PointsThe system probably doesn’t like that the redundant console logs are still there. Delete them and your code should be good :)
KRIS NIKOLAISEN
54,967 PointsAlso your initial value to log is 2. And there shouldn't be a semicolon after i++2.
KRIS NIKOLAISEN
54,967 PointsIt should be +=2
Darryl Mah
5,492 PointsDarryl Mah
5,492 PointsI didn’t look at the code very well. Good catch Kris...also does ++2 work? Or does it need to be +=2? I thought ++ just meant increment by one?