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Start your free trialKelly Vaden
8,743 PointsIssue with Slice Functions Challenge Task 2
Hi all,
I'm unable to pass the above mentioned challenge, but am not sure why.
The prompt: Make a new function named first_and_last_4. It'll accept a single iterable but, this time, it'll return the first four and last four items as a single value.
My code is attached.
When I run my code in a Jupyter notebook and pass in a test list of [1,2,3,4,5,6,7,8,9,10], I do get the expected result of [1,2,3,4,7,8,9,10]. The message within the Challenge Task "Didn't get the right results" is not very helpful for debugging.
Finally, a note on the function name: If I name the function "first_and_last_4" as the prompt suggests, I get the message "first_4 not found". If I name it "first_4" I get the message "Didn't get the right results from first_4." Which makes me suspect the code checking is looking for a function called first_4.
Any advice is appreciated!
def first_4(iterable):
first = iterable[0:4]
last = iterable[-4:]
result = first + last
return result
Kayc M
12,593 PointsOh and also you can't delete the task before, otherwise, it will throw an error:
def first_4(iterable):
first = iterable[0:4]
return iterable
def first_and_last_4(iterable):
first = iterable[0:4]
last = iterable[-4:]
result = first + last
return result
2 Answers
Steven Parker
231,269 PointsAs Kayc pointed out, it's important not to remove code from a previous task as you work on each new one. The challenge instructions even contain this reminder: "Important: In each task of this code challenge, the code you write should be added to the code from the previous task."
So at this point, you should have two different functions in the solution.
Kelly Vaden
8,743 PointsThanks, Kayc and Steven, for setting me straight! Clearly I misunderstood the instructions about leaving the first function as is and creating a new one for each challenge task.
Kayc M
12,593 PointsKayc M
12,593 PointsYou forgot to name the function (first_and_last_4)
It should be:
Nothing wrong with the code.