it does not work even if i replace "i" with "n". says check the values you are returning to the string.

Enter your FizzBuzz solution here! You will have to make some minor changes to get this to work with our editor though. Step 1: Copy-paste your code in between the comments shown below. Your solution is going inside a function I created. Don't worry about what it does, this just allows me to verify your solution. Step 2: Change your variable/constant name that you are checking in each step to n. For example if (n % 3 == 0). You also don't need to define n. It is defined in the function provided. Step 3: Change all your print statements to return statements. For example: print("FizzBuzz") becomes return "FizzBuzz". While these are very specific directions, they allow me to verify your solution precisely over a large number of possible answers. Note: Do not worry about the default case (where the number doesn't match Fizz, Buzz, or FizzBuzz). The code in the challenge editor already takes care of that by returning the number as a string using string interpolation. The challenge also does not need you to loop over a range of values (using for or while). I'll take care of that.

func fizzBuzz(n: Int) -> String {
  // Enter your code between the two comment markers
  for i in 1...100{
  if (i%3 == 0) && (i%5 == 0){
  print("FizzBuzz")
  } else if (i%3 == 0){
  print("Fizz")
  } else if (i%5 == 0){
  print("Buzz")
  } else {
  print(i)}
  }
  // End code
  return "\(n)"
}