Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

iOS Swift Basics (retired) Types Printing Results

John Ferreira
John Ferreira
2,766 Points

it doesn't accept let language = "Swift" println("Learning " + language) why not?

it doesn't accept

let language = "Swift"

println("Learning " + language)

why not?

println.swift
let language = "Swift"


println("Learning " + language)

3 Answers

Alexey Kuznetsov
Alexey Kuznetsov
9,516 Points

You need to interpolate it, not concatenate. Use that structure: println("Learning \(language)")

Alexey Kuznetsov
Alexey Kuznetsov
9,516 Points

Oops, missed the back slash before (language)

the direction of the slash is critical println("Learning (language)")