Welcome to the Treehouse Community
The Treehouse Community is a meeting place for developers, designers, and programmers of all backgrounds and skill levels to get support. Collaborate here on code errors or bugs that you need feedback on, or asking for an extra set of eyes on your latest project. Join thousands of Treehouse students and alumni in the community today. (Note: Only Treehouse students can comment or ask questions, but non-students are welcome to browse our conversations.)
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and a supportive community. Start your free trial today.

Susitha Herath Mudiyanselage
4,957 PointsIt is not passing!
// I have setup a java.io.Console object for you named console
String firstName = "Adam";
console.printf(firstName);
This step has an error which I can not figure out. please help!
// I have setup a java.io.Console object for you named console
String firstName = "Adam";
console.printf(firstName);
2 Answers

Rob Bridges
Full Stack JavaScript Techdegree Graduate 35,459 PointsHello!
You set your variable up correctly, but it looks like how you are formatting with the printf statement. whenever you want a pass a variable into it is use the %s symbol if you're pass in a string, and declare your variables after the string. The syntax looks like. console.printf("%s words making up your string", variable)
Also be sure to print exactly what they want to see, in this case it would be "<Your name> can code in Java!".
So it should look something like this.
console.printf("%s can code in Java!", firstName);

Susitha Herath Mudiyanselage
4,957 PointsThank you. It worked! yes I had to match the text within the double quotes "can code in java" just firstName would not be enough to pass the exercise. Thanks again.

Rob Bridges
Full Stack JavaScript Techdegree Graduate 35,459 PointsGlad to hear it helped.