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Java Java Basics Getting Started with Java Strings, Variables, and Formatting

Susitha Herath Mudiyanselage
Susitha Herath Mudiyanselage
4,957 Points

It is not passing!

// I have setup a java.io.Console object for you named console

String firstName = "Adam";

console.printf(firstName);

This step has an error which I can not figure out. please help!

Name.java
// I have setup a java.io.Console object for you named console

String firstName = "Adam";

console.printf(firstName);

2 Answers

Rob Bridges
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.a{fill-rule:evenodd;}techdegree seal-36
Rob Bridges
Full Stack JavaScript Techdegree Graduate 35,459 Points

Hello!

You set your variable up correctly, but it looks like how you are formatting with the printf statement. whenever you want a pass a variable into it is use the %s symbol if you're pass in a string, and declare your variables after the string. The syntax looks like. console.printf("%s words making up your string", variable)

Also be sure to print exactly what they want to see, in this case it would be "<Your name> can code in Java!".

So it should look something like this.

console.printf("%s can code in Java!", firstName);
Susitha Herath Mudiyanselage
Susitha Herath Mudiyanselage
4,957 Points

Thank you. It worked! yes I had to match the text within the double quotes "can code in java" just firstName would not be enough to pass the exercise. Thanks again.