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PHP PHP Basics Unit Converter Manipulating Numbers

It keeps saying I haven't changed $integerOne. so confused

I am following the previous video to do this task yet i seem to be doing something wrong. $integerOne = 1; $integerTwo = 2;

var_dump( $integerOne + 5); var_dump( $integerTwo - 1);


//Place your code below this comment
$integerOne = 1; ($integerOne + 5);
$integerTwo = 2; ($integerTwo - 1);
$floatOne = 1.5;


1 Answer

Jennifer Nordell
Jennifer Nordell
Treehouse Teacher

Hi there, jonny black ! You added 5 to $integerOne but then nothing happens with the results. You didn't echo or var_dump them so we can't see the results and they are not saved back into $integerOne.

You could do this:

$integerOne += 5;

Or this:

$integerOne = $integerOne + 5;

These two lines do the same thing, They add 5 onto $integerOne and then assign that result back into the $integerOne value overwriting the original. You will need this same type of thing for $integerTwo.

Hope this helps! :sparkles: