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stavros zografos
312 PointsIt logs undefined after the number 24!!
I 'm at the "Refactor Using a Loop" and I can't understand why after it logs the number 24 it also logs undefined.Here is my code:
for(var i = 0;i < 25;i++) { if(i % 2 === 0 && !i === 0) { console.log(i); } }
for(var i = 0;i < 25;i++) {
if(i % 2 === 0 && !i === 0) {
console.log(i)
}
};
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>JavaScript Loops</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>
2 Answers
andren
28,558 PointsWith this code: !i === 0 you are telling JavaScript to reverse i and compare it to 0, rather than reverse the result of that comparison. To do what you intended you need to wrap the comparison in a parenthesis like this: !(i === 0) or use the not equal comparison instead of using the NOT operator like this: i !== 0.
Doing that will make your code work, but it's worth nothing that your code is overly complicated. Instead of looping 24 times and only printing if the number is even and not 0, you could just start i at 2 and increase it by 2 each loop. Like this:
for(var i = 2;i < 25; i+= 2) {
console.log(i)
};
That will result in the same sequence of numbers being printed and is not only simpler code wise, but more efficient as well, since the loop has to run less times.
stavros zografos
312 PointsOk , thanks a lot! That solve my problem :)