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Python Python Collections (2016, retired 2019) Dictionaries Dictionary Basics

Enzo Cnop
Enzo Cnop
5,157 Points

It looks like task 1 is no longer passing.

I did this challenge before and went back for review. I can't figure out what I did wrong this time. The workspace lets task 1 pass, then says task 1 isn't passing when I try to pass task 2. I've tried a few different methods for nesting, but nothing seems to work. Any hints?

player = {"name": "Enzo", "remaining_lives": 3, "levels": [1, 2, 3, 4], dict([["items", "rock"]])}

2 Answers

Jennifer Nordell
Jennifer Nordell
Treehouse Teacher

Hi there, Enzo! I feel like you're getting creating a dictionary confused with accessing an element of a dictionary. So I'm going to go over the first step a bit and show you how we would access those dictionaries. I whipped up a small example in workspaces that you should be able to compile and run. My guess is that you will realize the mistake when you see the difference.

player = {"name": "Enzo", "remaining_lives": 3, "levels": [1, 2, 3, 4]}

print(player["name"])  #This prints the value of the player dictionary at the key "name"
print(player["remaining_lives"]) #This prints out the value of the player dictionary at the key "remaining lives"
print(player["levels"]) #This prints out the array associated with the key "levels" from the player dictionary

weapon = {"type": "sword", "details" : {"quality": "fine", "material": "steel"}}


weapon_details = weapon["details"]  

print("Our hero {} is carrying a {} {} {}!".format(player["name"], weapon_details["quality"], weapon_details["material"],  weapon["type"]))

What we're going for here is a dictionary inside of a dictionary. You already have a list assigned to a key. Now you just need to assign a dictionary to a key. Take a look at the above example and see if it doesn't clarify things a bit.

Hope this helps! :sparkles:

The last element in your dictionary doesn't have the proper syntax. You forgot to put a key before the value.