Welcome to the Treehouse Community

The Treehouse Community is a meeting place for developers, designers, and programmers of all backgrounds and skill levels to get support. Collaborate here on code errors or bugs that you need feedback on, or asking for an extra set of eyes on your latest project. Join thousands of Treehouse students and alumni in the community today. (Note: Only Treehouse students can comment or ask questions, but non-students are welcome to browse our conversations.)

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and a supportive community. Start your free trial today.

Python Python Collections (2016, retired 2019) Dictionaries Dictionary Basics

Enzo Cnop
Enzo Cnop
5,157 Points

It looks like task 1 is no longer passing.

I did this challenge before and went back for review. I can't figure out what I did wrong this time. The workspace lets task 1 pass, then says task 1 isn't passing when I try to pass task 2. I've tried a few different methods for nesting, but nothing seems to work. Any hints?

dicts.py
player = {"name": "Enzo", "remaining_lives": 3, "levels": [1, 2, 3, 4], dict([["items", "rock"]])}

2 Answers

Jennifer Nordell
seal-mask
STAFF
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher

Hi there, Enzo! I feel like you're getting creating a dictionary confused with accessing an element of a dictionary. So I'm going to go over the first step a bit and show you how we would access those dictionaries. I whipped up a small example in workspaces that you should be able to compile and run. My guess is that you will realize the mistake when you see the difference.

player = {"name": "Enzo", "remaining_lives": 3, "levels": [1, 2, 3, 4]}

print(player["name"])  #This prints the value of the player dictionary at the key "name"
print(player["remaining_lives"]) #This prints out the value of the player dictionary at the key "remaining lives"
print(player["levels"]) #This prints out the array associated with the key "levels" from the player dictionary

weapon = {"type": "sword", "details" : {"quality": "fine", "material": "steel"}}

print(weapon["type"])

weapon_details = weapon["details"]  

print("Our hero {} is carrying a {} {} {}!".format(player["name"], weapon_details["quality"], weapon_details["material"],  weapon["type"]))

What we're going for here is a dictionary inside of a dictionary. You already have a list assigned to a key. Now you just need to assign a dictionary to a key. Take a look at the above example and see if it doesn't clarify things a bit.

Hope this helps! :sparkles:

The last element in your dictionary doesn't have the proper syntax. You forgot to put a key before the value.