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Java Java Basics Perfecting the Prototype Looping until the value passes

Posted by Nila Palmo Ram
Nila Palmo Ram
4,303 Points

It says my code took too long to run what should I do?

Can you please tell me if it is a syntax error or something to do with the server.

Example.java 
// I have initialized a java.io.Console for you. It is in a variable named console.
String response;
console.printf("Do you understand do while loops?  ");
 {
response = console.readLine ("Do you understand do while loops?  ");
} while(response.equals("No"));

1 Answer

Jennifer Nordell
seal-mask
STAFF
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher
Jennifer Nordell
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher

Hi there! It is not really a syntax error nor is it a problem with the server. This code will not produce a syntax error (it will compile without problem), but what you have here is what we call a runtime error. This is an error that occurs while the program is running but didn't cause a compiler error and it is generally a logic flaw. In this case, you left off the do part of the do while loop. You created an infinite loop inadvertently.

// I have initialized a java.io.Console for you. It is in a variable named console.
String response;

do {  // do this
     response = console.readLine ("Do you understand do while loops?  ");  // Set the response to the user's input
} while(response.equals("No"));  // when the answer is NOT "No" exit the loop

Hope this helps, but let me know if you have any questions! :sparkles:

Nila Palmo Ram
Nila Palmo Ram
4,303 Points

Thank you so much!!