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JavaScript

Posted by angelod
angelod
6,694 Points

it works but don't understand why return random; was needed

https://w.trhou.se/h6krtc50je

without return random; the code wouldn't had work, but don't understand why it makes it work.

1 Answer

Justin Cantley
Justin Cantley
18,068 Points
Justin Cantley
Justin Cantley
18,068 Points

This is your function that returns a random number:

function randomNumber() {
 var random = Math.floor(Math.random() * 256 );
  return random;
}

If you wrote it simply like this:

function randomNumber() {
 var random = Math.floor(Math.random() * 256 );
}

it would assign a random value to the random variable every time, but that's all it would do. It doesn't give you back any value. It simply performs the function.

Using return random is what allows you to get the result of the function that was called.