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Python Python Collections (2016, retired 2019) Sets Set Math

Kars Jansens
Kars Jansens
5,348 Points
Posted by Kars Jansens
Kars Jansens
5,348 Points

It works in workspace {python}

question: let's write some functions to explore set math a bit more. We're going to be using this COURSES dict in all of the examples. Don't change it, though!

So, first, write a function named covers that accepts a single parameter, a set of topics. Have the function return a list of courses from COURSES where the supplied set and the course's value (also a set) overlap.

For example, covers({"Python"}) would return ["Python Basics"].

When i try this in my workspace it totaly works so I do not understand why I get a bummer.

sets.py 
COURSES = {
    "Python Basics": {"Python", "functions", "variables",
                      "booleans", "integers", "floats",
                      "arrays", "strings", "exceptions",
                      "conditions", "input", "loops"},
    "Java Basics": {"Java", "strings", "variables",
                    "input", "exceptions", "integers",
                    "booleans", "loops"},
    "PHP Basics": {"PHP", "variables", "conditions",
                   "integers", "floats", "strings",
                   "booleans", "HTML"},
    "Ruby Basics": {"Ruby", "strings", "floats",
                    "integers", "conditions",
                    "functions", "input"}
}

def covers(arg):
    lista = []
    if COURSES["Python Basics"].intersection(arg) == arg:
        lista.append("Python Basics")
    elif COURSES["Java Basics"].intersection(arg) == arg:
        lista.append("Java Basics")
    elif COURSES["PHP Basics"].intersection(arg) == arg:
        lista.append("PHP Basics")
    elif COURSES["Ruby Basics"].intersection(arg) == arg:
        lista.append("Ruby Basics")
    else:
        lista.append("hoi")
    return lista

1 Answer