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PHP PHP Basics Daily Exercise Program Conditionals

Mike Coding
Mike Coding
1,883 Points

It writes that the output is incorrect

I tried to fix it but it keeps writing that my output is incorrect. What should I do?


//Place your code below this comment
$studentOneName = 'Dave';
$studentOneGPA = 3.8;

$studentTwoName = 'Treasure';
$studentTwoGPA = 4.0;
 if ($studentOneGPA==4.0){
   echo $studentOneName.'made the Honor Roll';
  echo $studentOneName.'NAME has a GPA:'.$studentOneGPA;
 if ($studentTwoGPA==4.0){
   echo $studentTwoName.'made the Honor Roll';
  echo $studentTwoName.'NAME has a GPA:'.$studentTwoGPA;


1 Answer

The problem is in your strings. For the output to be correct you must have spaces between the variable value and the concatenated string, so on your code you'll add those on your strings. Also, in both else statements you forgot to delete the placeholder 'NAME' and exchanged ' of ' for ' : '.


if ($studentOneGPA === 4.0){
    // The spaces around the concatenation operator are optional, but inside the string the space is vital for a correct output.
   echo $studentOneName . ' made the Honor Roll';
 } else { 
    // 'has a GPA of ' instead of 'GPA:'
  echo $studentOneName . ' has a GPA of '.$studentOneGPA;
 if ($studentTwoGPA === 4.0){
   echo $studentTwoName . ' made the Honor Roll';
  echo $studentTwoName . ' has a GPA of '.$studentTwoGPA;