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JavaScript JavaScript Loops, Arrays and Objects Simplify Repetitive Tasks with Loops Refactor Using a Loop

Posted by seattler
seattler
2,067 Points

I've built a solid 'for loop.' Yet, it says I'm only logging it once. How do increase my code without += console.log?

//I built the for loop like this

for (i = 2; i <=24; i +=2) { console.log(i); }

The goal is to print even numbers 2 through 24. The error I'm given is that I'm only logging one number rather then several. What am missing??

script.js 
for (i = 2; i <=24; i+=2); {
 console.log(i);
}
index.html 
<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <title>JavaScript Loops</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>

2 Answers

rtholen
rtholen
Courses Plus Student 11,859 Points

Your code shows a semicolon after the parenthesis in the for loop. Should be after the 2. As is the loop runs through all its iterations doing nothing because there is nothing specified to do between the parenthesis and the semicolon. Then it performs a single console log output after finishing the loop.

Adrienne Cabouet
Adrienne Cabouet
3,284 Points
Adrienne Cabouet
Adrienne Cabouet
3,284 Points

You're semi-colons in your for loop conditions when you should be using commas between each parameter and then nothing but a curly bracket after the last parenthesis:

for (i = 2, i <=24, i+=2) { console.log(i); }