Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

iOS Swift 2.0 Collections and Control Flow Control Flow With Conditional Statements FizzBuzz

Posted by jc laurent
jc laurent
6,351 Points

I've pasted it exactly as the solution provided and can't even pass

are we kidding?

fizzBuzz.swift 
func fizzBuzz(n: Int) -> String {
  // Enter your code between the two comment markers
   if (n % 3 == 0) && (n % 5 == 0) {
        print("FizzBuzz")

    }else if (n % 3 == 0) {
        print("Fizz")

    }else if (n % 5 == 0) {
        print("Buzz")

    }else{
       print(n)
    }

  // End code
  return "\(n)"
}

2 Answers

jc laurent
jc laurent
6,351 Points

Thks Bud, I shouldn't stayed too long front of the screen!

David Papandrew
David Papandrew
8,386 Points
David Papandrew
David Papandrew
8,386 Points

Hi JC,

Your code is close, but not quite right. Your function is supposed to return a string, but instead, you will notice that your conditional statements print FizzBuzz, Fizz and Buzz rather than return those strings.

So if you change all the print statements to "return". It should work. See the code below:

func fizzBuzz(n: Int) -> String {
    // Enter your code between the two comment markers
    if (n % 3 == 0) && (n % 5 == 0) {
        return "FizzBuzz"

    } else if (n % 3 == 0) {
        return "Fizz"

    } else if (n % 5 == 0) {
        return "Buzz"

    } else{
        return "\(n)"
    }

    // End code
    return "\(n)"
}