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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Posted by NARCIS MATABOSCH
NARCIS MATABOSCH
1,540 Points

I've tried this code in Pycharm and it works... What am I doing wrong?

I think this code is correct...i've tried this in several examples.

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(my_string):
    my_dict = {}
    for word in my_string.lower().split(' '):
        try:
            my_dict[word]
        except KeyError:
            my_dict[word] = 1
        else:
            my_dict[word] += 1
    return my_dict
NARCIS MATABOSCH
NARCIS MATABOSCH
1,540 Points

Nevermind, writting this "for word in my_string.lower().split('):" instead of "for word in my_string.lower().split(' '):" has passed the test.

Anyway, this doesn't make sense, right?

1 Answer