Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Python Collections (2016, retired 2019) Dictionaries Word Count

Posted by NARCIS MATABOSCH
NARCIS MATABOSCH
1,540 Points

I've tried this code in Pycharm and it works... What am I doing wrong?

I think this code is correct...i've tried this in several examples.

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(my_string):
    my_dict = {}
    for word in my_string.lower().split(' '):
        try:
            my_dict[word]
        except KeyError:
            my_dict[word] = 1
        else:
            my_dict[word] += 1
    return my_dict
NARCIS MATABOSCH
NARCIS MATABOSCH
1,540 Points

Nevermind, writting this "for word in my_string.lower().split('):" instead of "for word in my_string.lower().split(' '):" has passed the test.

Anyway, this doesn't make sense, right?

1 Answer