Welcome to the Treehouse Community

The Treehouse Community is a meeting place for developers, designers, and programmers of all backgrounds and skill levels to get support. Collaborate here on code errors or bugs that you need feedback on, or asking for an extra set of eyes on your latest project. Join thousands of Treehouse students and alumni in the community today. (Note: Only Treehouse students can comment or ask questions, but non-students are welcome to browse our conversations.)

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and a supportive community. Start your free trial today.

Python Python Collections (2016, retired 2019) Dictionaries Word Count

I've tried this code in Pycharm and it works... What am I doing wrong?

I think this code is correct...i've tried this in several examples.

wordcount.py
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(my_string):
    my_dict = {}
    for word in my_string.lower().split(' '):
        try:
            my_dict[word]
        except KeyError:
            my_dict[word] = 1
        else:
            my_dict[word] += 1
    return my_dict

Nevermind, writting this "for word in my_string.lower().split('):" instead of "for word in my_string.lower().split(' '):" has passed the test.

Anyway, this doesn't make sense, right?

1 Answer