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JavaScript JavaScript Foundations Functions Return Values

Michael Criste
Michael Criste
5,045 Points
Posted by Michael Criste
Michael Criste
5,045 Points

I've tried various approaches but without success. It's a syntax error that I need help with.

I understand the concepts just fine. I tried using "" in place of string. I tried Fixnum in place of number. I tried [] in place of array. I'm pretty sure I tried the variables with quotes around them, like in the question: 'string,' 'number,' etc.

Help!

index.html 
<!DOCTYPE html>
<html lang="en">
  <head>
    <title>JavaScript Foundations: Functions</title>
    <style>
      html {
        background: #FAFAFA;
        font-family: sans-serif;
      }
    </style>
  </head>
  <body>
    <h1>JavaScript Foundations</h1>
    <h2>Functions: Return Values</h2>
    <script>

      function arrayCounter (array) {
        if (typeof array === string){ 
          return 0;
        }
        elsif (typeof array === number) {
          return 0;
        }
        elsif (typeof array === 'undefined') { 
          return 0;
        }
        else 
          return array.length;
          }

    </script>
  </body>
</html>

3 Answers

William Li
PLUS
William Li
Courses Plus Student 26,868 Points
William Li
William Li
Courses Plus Student 26,868 Points

Hi, a few things need to be fixed

  • no elsif keyword in JavaScript, use else if.
  • "string" and "number" instead of just string, number when checking for equality with the output of typeof 
       function arrayCounter(array) {
        if (typeof(array) === "string"){ 
          return 0;
        }
        else if (typeof(array) === "number") {
          return 0;
        }
        else if (typeof(array) === 'undefined') { 
          return 0;
        }
              else {
          return array.length;
          }
      }
Richard Ling
Richard Ling
8,522 Points
Richard Ling
Richard Ling
8,522 Points

Hi Michael,

You have used "elsif", instead of "else if", so:

function arrayCounter (array) {
    if (typeof array === string) { 
        return 0;
    } else if (typeof array === number) {
        return 0;
    } else if (typeof array === 'undefined') { 
        return 0;
    }
    else 
        return array.length;
}

Hope this helps :)

Thanks, Rich

Ian Hattendorf
Ian Hattendorf
7,715 Points
Ian Hattendorf
Ian Hattendorf
7,715 Points

Hi Michael, you have two issues with your code. First, you need to use else if instead of elsif. Second, typeof returns a string, so you need to compare typeof array to 'string' instead of string, same with number.