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Java Java Basics Getting Started with Java IO

Edward Asafu-Adjaye
PLUS
Edward Asafu-Adjaye
Courses Plus Student 1,415 Points
Posted by Edward Asafu-Adjaye
Edward Asafu-Adjaye
Courses Plus Student 1,415 Points

Java Basics - challenge parameter issues

Hey guys,

Can anyone help i keep getting this bummer error Error: Bummer! Did you forget to pass the lasttName parameter to the printf function?

My code is attached any helped would be most grateful.

Thanks

IO.java 
// I have imported java.io.Console for you.  It is a variable called console.
String firstName = console.readLine("What is your name?  ");
console.printf("Hello my name is %s\n", firstName);
console.printf("%s is learning how to write java\n", firstName);
String lastName = console.readLine("What is your name?  ");
console.printf("Hello my name is %s\n", lastName);
console.printf("%s is learning how write java\n", lastName);
console.printf("First name:", firstName);
console.printf("Last name:", lastName);
Daniel Hildreth
Daniel Hildreth
16,170 Points
Daniel Hildreth
Daniel Hildreth
16,170 Points

Hi there guys. I'm having this same issue and getting the parameter error. I have the following code. Can someone tell me what I'm doing wrong with my code so I can solve this challenge? I didn't want to just copy and paste others' answers. That is why I pasted my own code here.

// I have imported java.io.Console for you.  It is a variable called console.
String firstName = console.readLine("What is your first name?  ");
console.printf("Hello, my first name is %s\n", firstName);
console.printf("%s is learning Java\n", firstName);
String lastName = console.readLine("What is your last name?  ");
console.printf("My last name is %s\n", lastName);
console.printf("First name: %s", firstName);
console.printf("Last name: %s", lastName);

4 Answers

Kumar Bharath H N
Kumar Bharath H N
8,324 Points
Kumar Bharath H N
Kumar Bharath H N
8,324 Points

Hey Edward,

There is one small mistake in your printf statement, when you use printf you need to use something called format specifiers like %d for integers and %s for String so that the compiler will know where to place those arguments you write after the ,(comma). all you have to do is add %s

console.printf("First name: %s", firstName);
console.printf("Last name: %s", lastName);
Jon Kussmann
PLUS
Jon Kussmann
Courses Plus Student 7,254 Points
Jon Kussmann
Jon Kussmann
Courses Plus Student 7,254 Points

To do parts 3 and 4 of this challenge, you still need to add the appropriate "%s" to fill in the first and last names.

console.printf("First name: %s", firstName);

You can do something similar with lastName to complete the challenge.

Iain Diamond
Iain Diamond
29,379 Points
Iain Diamond
Iain Diamond
29,379 Points

Hi Edward,

console.printf("First name:", firstName);
console.printf("Last name:", lastName);

I believe the compiler warning is slightly misleading. The solution, if I recall correctly, is you need to add a %s to the last two printf lines to display the first and last names.

Hope this helps, iain

Edward Asafu-Adjaye
PLUS
Edward Asafu-Adjaye
Courses Plus Student 1,415 Points
Edward Asafu-Adjaye
Edward Asafu-Adjaye
Courses Plus Student 1,415 Points

WOW thank you all for such expedite responses. Really really helpful. Thank you very much :-) Iain Diamond kumar bharath hassan narasimha murthy Jon Kussmann

I can continue my journey.