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Java Java Basics Perfecting the Prototype String Equality

Jordi Escolà Soldevila
Jordi Escolà Soldevila
807 Points
Posted by Jordi Escolà Soldevila
Jordi Escolà Soldevila
807 Points

Java Basics equals

I am writing this code:

String firstExample = "hello"; String secondExample = "hello"; if (firstExample.equals(secondExample)) { console.printf("first is equal to second"); System.exit(0); } String thirdExample = "HELLO";

And i think it is correct but is not working.

I will keep doing the other lessons.

Equality.java 
// I have imported a java.io.Console for you, it is named console. 
String firstExample = "hello";
String secondExample = "hello";
if (firstExample.equals(secondExample)) {
  console.printf("first is equal to second");
                 System.exit(0);
                 }
String thirdExample = "HELLO";
Jordi Escolà Soldevila
Jordi Escolà Soldevila
807 Points
Jordi Escolà Soldevila
Jordi Escolà Soldevila
807 Points

I've found the anwer. System exit shouldnt be there.

1 Answer

Alexander Davison
Alexander Davison
65,469 Points
Alexander Davison
Alexander Davison
65,469 Points

You don't need to call System.exit(0).

// I have imported a java.io.Console for you, it is named console. 
String firstExample = "hello";
String secondExample = "hello";
String thirdExample = "HELLO";

if (firstExample.equals(secondExample)) {
  console.printf("first is equal to second");
}

I hope this helps. ~Alex