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Java Java Basics Perfecting the Prototype Conditional ints

Ting-Chieh Huang
Ting-Chieh Huang
3,387 Points
Posted by Ting-Chieh Huang
Ting-Chieh Huang
3,387 Points

Java inheritance (overloading methods in subclass over super class)

I remember we are allowed to overload and override methods in subclass. But why this code (overload) doesn't work?

class practice{
    public static void main(String args[]){

        Bar Treehouse[] = new Bar[2];

        Treehouse[0]=new Baz();
        Treehouse[0].doBar(3); //this one works
        Treehouse[0].doBar(3,4);  // why this one doesn't work?
    }



}


 class Bar {
      public void doBar(int x) {
          System.out.println("this is dobar"+ x);
          }
      }




    class Baz extends Bar {
      public void doBar(int x, double y) {
          System.out.println("x and y"+ x +" "+y);
      }
    }

1 Answer

Dan Johnson
Dan Johnson
40,532 Points
Dan Johnson
Dan Johnson
40,532 Points

When you overload a method, it's basically creating an entirely new method with no direct association with the other of the same name, it's the signature that matters. So in your example doBar with two arguments only is known by the sub class.

Here's an example of overriding a method:

public class Application {
    public static void main(String[] args) {
        Super[] examples = {new Super(), new Sub()};

        examples[0].overriding();
        examples[1].overriding();
    }
}

class Super { 
    public void overriding() {
        System.out.println("Super class");
    }
}

class Sub extends Super {
    // Notice the equivalent function signatures.
    @Override
    public void overriding() {
        System.out.println("Sub class");
    }
}

Note that the @Override annotation isn't required, but it'll help you catch logic errors if you don't match up the function signatures.