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Christoffer Boye-Hansen
3,810 PointsJava: Missing the 'length' property on your strings
So my challenge is: Sort the 'saying2' array, on about line 19, so that the words are listed in length order. The shortest first. Use the 'length' property on the strings in the sort function.
My script currently looks like this: <script> var saying1 = ["The", "quick", "brown", "fox", "jumps", "over", "the", "lazy", "dog"]; var saying2 = ["The", "quick", "brown", "fox", "jumped", "over", "the", "lazy", "dog's", "back"]; saying1.reverse(); saying2.sort(function() { });
Then I thought I could do like this, but then it says that task 1 is no longer passing.
<script> var saying1 = ["The", "quick", "brown", "fox", "jumps", "over", "the", "lazy", "dog"]; var saying2 = ["The", "quick", "brown", "fox", "jumped", "over", "the", "lazy", "dog's", "back"]; saying1.reverse(); saying2.sort(function() { return saying2.length(); });
How do I call .length inside the function?
2 Answers
Jason Anello
Courses Plus Student 94,610 PointsHi Christoffer,
I believe the video ran through how to sort numbers in an array.
It was something like:
numbers.sort(function(a, b) {
return a - b;
});
So the sort method would pass in two numbers from the array into the compare function and the compare function would return a positive, negative, or zero value to indicate the relative order of a and b
You want to do something very similar here. Except that 2 strings from the array are going to be passed in and you want to subtract their lengths.
saying2.sort(function(a, b) {
return a.length - b.length;
});
Bob Sutherton
20,160 PointsI had to ask on that one too!