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Java

Posted by Gem Knight
Gem Knight
4,779 Points

Java Objects

I am learning the lesson Java objects and I am not sure why my code isn't working. Please help. Example.java

public class Example {

public static void main(String[] args) {
    // Your amazing code goes here...
System.out.println("We are making a new Pez Dispenser.");
PezDispenser dispenser = new PezDispenser();
System.out.printf("The dispenser character is %s\n", dispenser.mCharacterName);    
}

}

PezDispenser.java

public class PezDispenser {

public static void main(String[] args) { public String mCharacterName = "Jedi";

} }

1 Answer

jcorum
jcorum
71,830 Points
jcorum
jcorum
71,830 Points

I don't remember the class, and you didn't give a link, so here's my best guess:

First, when you create a new PezDispenser you need to give the dispenser a name, as an actual parameter for the call to the PezDispenser constructor

public class Example {

    public static void main(String[] args) {
        // Your amazing code goes here...
        System.out.println("We are making a new Pez Dispenser.");
        PezDispenser dispenser = new PezDispenser("Jedi");  //requires a name as the parameter
        System.out.printf("The dispenser character is %s\n", dispenser.mCharacterName);    
    }
}

Second, you don't want to have a static main method in this class. This class is the "blueprint" for PezDispenser objects.

You do need an instance variable mCharacterName, and you need a constructor that will take a passed in name, e.g., "Jedi", and store it in the instance variable:

public class PezDispenser {
    String mCharacterName;

    public PezDispenser(String characterName) { 
        mCharacterName = characterName;
    } 
}

So now, when you call the constructor in Example: PezDispenser dispenser = new PezDispenser("Jedi"); , you pass in a name, and the constructor takes it and stores it in the mCharacterName variable in the dispenser object.