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Java

Posted by Fahman Khan
Fahman Khan
3,798 Points

Java Strings

Apparently, I have been studying java for past year; however, i have never encountered a code like this.

OkHttpClient client = new OkHttpClient();

String run(String url) throws IOException { Request request = new Request.Builder() .url(url) .build();

Response response = client.newCall(request).execute(); return response.body().string(); }

I don't seem to understand whats going on after String run...I want to say thats some function, but then i'm pretty sure its not. Moreover, i thought of it as a creation of a String variable, but i'm not sure. Can anyone explain to me what this code is or whats its doing?

3 Answers

Craig Dennis
STAFF
Craig Dennis
Treehouse Teacher
Craig Dennis
Craig Dennis
Treehouse Teacher

Yeah that is just a method definition using the default access level (y'know like private/public which is protected).

It is a method called run that returns a String

Radim Štěpaník
Radim Štěpaník
157 Points
Radim Štěpaník
Radim Štěpaník
157 Points

It is function which returns string value. It is similar to write

//probably global prom
OkHttpClient client = new OkHttpClient();

//function which must return String value, "throws IOException" means that IOException can be thrown by running this code, more you can read here http://stackoverflow.com/questions/11589302/why-is-throws-exception-necessary-when-calling-a-function
protected String run(String url) throws IOException {
   // creation new request to url
     Request request = new Request.Builder() .url(url) .build();
   // execute request and catch response
     Response response = client.newCall(request).execute(); 
  // return string value of response body 
     return response.body().string(); }
Fahman Khan
Fahman Khan
3,798 Points

Thank you! :)