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JavaScript JavaScript Basics (Retired) Storing and Tracking Information with Variables Using String Methods


The userName variable is "undefined" not "23188XTR#SMITH".

var id = "23188xtr";
var lastName = "Smith";

var userName = console.log(id.toUpperCase()   + "  #  " +  lastName.toUpperCase() );
  <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
  <title>JavaScript Basics</title>
<script src="app.js"></script>

3 Answers

Ferdinand Pretorius
Ferdinand Pretorius
18,705 Points

Hi SuneethaRani Savaram,

You don't need to log it to the console!

All you need is this

var userName = id.toUpperCase()+ "#" + lastName.toUpperCase();

Hope this helps!

Thank you Sir.

Ferdinand Pretorius
Ferdinand Pretorius
18,705 Points

You are welcome buddy.

Good luck with your coding endeavours!

Lorenzo Minto
Lorenzo Minto
13,898 Points

It says it's undefined because you're trying to assign to userName the return value of the function console.log. You should assign to userName only the string concatenation, so just take off the console.log part and the parenthesis. It should look something like this:

var id = "23188xtr";
var lastName = "Smith";

var userName = id.toUpperCase()   + "#" +  lastName.toUpperCase()

Hope this helps.

Thank you sir,