Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

JavaScript JavaScript Basics (Retired) Creating Reusable Code with Functions Passing an Argument to a Function

JavaScript Basics Challenge Question!

Maybe it's my exhaustion, but I'm running out of time to get this done and I'm really stumped as to what this is asking me to do!

"After your newly created returnValue function, create a new variable named echo. Set the value of echo to be the results from calling the returnValue function. When you call the returnValue function, make sure to pass in any string you'd like for the parameter. The function will accept the string you pass to it and return it back (using the return statement). Then your echo variable will be set with what is returned, the results."

function returnValue(argument) {
  return argument;

var echo = argument;
  <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
  <title>JavaScript Basics</title>
<script src="script.js"></script>

1 Answer

Lee Vaughn
.a{fill-rule:evenodd;}techdegree seal-36
Lee Vaughn
Treehouse Teacher

You are really close!

You just need to replace 'argument' in your echo variable with the code you wrote on the line above it.

It should look like this:

function returnValue (argument) {
  return argument;

var echo = returnValue('help!');

Thank You Thank You!!! Of course that's what it was! Mom + working 60+ hours/week + school = goo for brains!