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Andy Durette
31,183 PointsJavaScript Functions Question
I am wondering why my code here
function arrayCounter (x) {
if (typeof x !== 'array'){
return 0;
}else
return x.length;
}
Will not pass this JavaScript challenge http://teamtreehouse.com/library/return-values
However this JavaScript will
function arrayCounter (array) {
if (typeof array === 'undefined' ||typeof array === 'string'||typeof array === 'number') {
return 0;
}
return array.length;
}
Doesn't the two code blocks do the same thing since I set that if the typeof was not equal to array it should return 0.
1 Answer
Alexander Costa
11,464 Pointstypeof thinks of arrays as objects
other wise your code says "if type of x is not a an array return 0" which would not work because like the second code suggests we are looking for typeof undefined, string, and number.