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JavaScript

Posted by Monkey D Luffy
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Monkey D Luffy
iOS Development Techdegree Student 4,919 Points

JavaScript Prototype Lesson-Function returns the actual function instead of the intended console log.

I'm using the exact same code as the lesson here and when I call the function using jim.greet I actually get the code from the function instead of the console.log output. Any ideas on what is going on.

ar personProtoype = { // name: "Anonymous", // greet: function (name, mood) { // name = name || "You"; // mood = mood || "good";

// console.log("Hello, "+ name + // " I am " + this.name + // " and I am in a " + mood + " mood!"); // },

// species: 'Homo Sapien', // };

// function Person (name) { // this.name = name; // }

// Person.prototype = personProtoype

// jim = new Person("Jim");

Oupt on the console

jim.greet

function (name, mood) { name = name || "You"; mood = mood || "good";

    console.log("Hello, "+ name + 
        " I am " + this.name + 
        " and I am in a " + mood + " mood!");} functions.js:61
Ajinkya Borade
Ajinkya Borade
Courses Plus Student 16,635 Points

Monkey D Luffy can u repost ur code, or use jsfiddle.com to show code Im not able to read through.

1 Answer

Brandon Flade
Brandon Flade
2,769 Points
Brandon Flade
Brandon Flade
2,769 Points

Hi Monkey D Luffy ,

It looks like you are referencing the function vs. actually calling it. If you call jim.greet("Monkey","Amazing"); you should get Hello, Monkey I am Jim and I am in a Amazing mood!