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Java Java Basics Getting Started with Java Strings, Variables, and Formatting

Posted by Ioan Popaluca
Ioan Popaluca
654 Points

java.util.MissingFormatArgumentException: Format specifier '%s' ()

i keep getting this error, even thou i put the right selector

Name.java 
// I have setup a java.io.Console object for you named console
String firstName = "Andreea";
console.printf("%s can code in Java!, firstName");

1 Answer

Bradley Williams
Bradley Williams
4,545 Points
Bradley Williams
Bradley Williams
4,545 Points

Hello, when using the formatted print method (printf) the argument should be passed after closing off the string and after a comma. The compiler is saying okay I have this string and the format specifier but nothing to replace it with. So, simply moving the firstName variable name after the ending double quote and after a comma, your code will work