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Start your free trialMohsen Qaddoura
22,237 Pointsjquery and ajax office status project sidebar employeeList div is not rendered
query and ajax office status project sidebar employeeList div is not rendered here is my widget.js :
$(document).ready(function() { var url = "../data/employees.json"; $.getJSON(url, function (response) { var statusHTML = '<ul class="bulleted">'; $.each(response, function (index, employee){ if (employee.inoffice === true) { statusHTML +='<li class="in">'; } else { statusHTML += '<li class="out">'; } statusHTML += employee.name + '</li>'; }); statusHTML += '</ul>'; $('#employeeList').html(statusHTML); }; // end getJSON }); // end ready
And index.html header:
<!DOCTYPE html> <html> <head> <meta charset="utf-8"> <title>AJAX Office Status Widget</title> <link href='http://fonts.googleapis.com/css?family=Varela+Round' rel='stylesheet' type='text/css'> <link rel="stylesheet" href="css/main.css"> <script src="http://code.jquery.com/jquery-1.11.1.min.js"></script> <script src="js/widget.js"></script> </head>
2 Answers
Mohsen Qaddoura
22,237 PointsI resolved the issue just now, If you check my code above you will find out that I forgot to close the parentheses for the getJSON function like this: }); // end getJSON This was the only issue!
Thanks for the reply.
Misha Shaposhnikov
8,718 PointsYou forgot to add the <li> and </li> tags between the employee names.
Should be like this:
var statusHTML = "<ul class='bulleted'>";
$.each(response, function (index,employee) {
if(employee.inoffice){
statusHTML += '<li class="in">'
}
else{
statusHTML += '<li class="out">'
}
statusHTML += employee.name + '</li>'
}); // end each
statusHTML += "</ul>"