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Jessica McGinn
11,378 PointsJQuery and AJAX task 3 of 3
This is my code..dunno what's wrong with it but its not passing...
var callback = function(response) {
$('#footer').html();
};
$.get("footer.html", callback);
5 Answers
Jessica McGinn
11,378 PointsFigured it out... to finish it I had to add the name of the function - 'response' - to the .html, silly mistake!
Thanks for all your help!
$.get("footer.html", function (response) {
$('#footer').html(response);
});
Dave McFarland
Treehouse TeacherHi Jessica McGinn ,
Your code would work, but it's not what the code challenge is asking for. This particular challenge is asking you to use the technique where you pass an anonymous function in as the second argument to the $.get() method:
$.get("footer.html", function (response) {
});
However, your approach would work just fine in a real application.
Sorry for the confusion.
Sander de Wijs
Courses Plus Student 22,267 PointsYou should add an anonymous function inside the $.get method
$.get("footer.html", function(response){
});
Jessica McGinn
11,378 PointsThanks both for your answers. So I've tried adding that:
var callback = function(response) {
$('#footer').html();
};
$.get("footer.html", function (response));
Is this what you meant or am I missing the point :)
Dave McFarland
Treehouse TeacherYou can get rid of this part:
var callback = function(response) {
$('#footer').html();
};
Also the, $.get part should look like this:
$.get("footer.html", function (response) {
});