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PHP

Robert Marczak
Robert Marczak
12,358 Points
Posted by Robert Marczak
Robert Marczak
12,358 Points

Json and php

How do I read json object send with $.ajax in php file. One of the arguments send within $.ajax is data: post_data. In js file post_data is an a js object with some static values.

var post_data = {
    "news_data" : 'hello',
    "news_date" : '1st march'
  }

and ajax request

$.ajax({
    url : 'news.php',
    dataType : 'json',
    type : 'post',
    data : post_data,
    success : function(data){
        console.log(data);
    }
  });
}

I can't figure out how to read sent data in php file

3 Answers

Joe Cochran
Joe Cochran
18,249 Points
Joe Cochran
Joe Cochran
18,249 Points

I think you are looking for json_decode(). news.php will receive post_data in $_POST. Use json_decode() on that to get an object or array that you can work with in php. See:

http://php.net/manual/en/function.json-decode.php

Robert Marczak
Robert Marczak
12,358 Points
Robert Marczak
Robert Marczak
12,358 Points

I decode it in php than encode it back and send it back to js file and print it in the console to see what I have. I get null. This is my full code

//create function to send ajax request
function ajax_request(){
  console.log("hello");
var post_data = {
    "news_data" : 'hello',
    "news_date" : '1st march'
  }

  $.ajax({
    url : 'news.php',
    dataType : 'json',
    type : 'post',
    data : post_data,
    success : function(data){
        console.log(data);
    }
  });
}

//on click event
$('#news_post_button').on('click', ajax_request);

and php file

<?php
header('Content-Type: application/json');
$aRequest = json_decode($_POST);

echo json_encode($aRequest);

?>

Php code is purely for testing.

Joe Cochran
Joe Cochran
18,249 Points

Is the data by chance stored in $_POST["post_data"] instead of just $_POST?