PHP Build a Basic PHP Website (2018) Building a Media Library in PHP Variables and Conditionals

Keep getting a code couldnt run error, and saying it contacted the email. Can't pass this step :/

Whenever i try to run my code, it doesnt work. gives me an error

index.php
<?php
$flavor = "cookie dough";
echo "<p>Your favorite flavor of ice cream is ";
echo $flavor;
echo ".</p>";
echo "<p>Hal's favorite flavor is cookie dough, also!</p>";

?>

1 Answer

Tobias Helmrich
Tobias Helmrich
31,595 Points

Hey Sam,

you forgot to put a conditional around your last echo statement. If you add this it should work, good luck!

if($flavor == "cookie dough") {
  echo "<p>Hal's favorite flavor is cookie dough, also!</p>";
}

I had that. I submitted this report after the first 3 times. But i figured it out anyways. thanks