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SONU PRABHAKAR
2,039 PointsKindly help me to solve this temperature conversion function...
i have written question in snippet below.
// Enter your code below
func temperatureInFahrenheit (temperature: Double) -> Double{
temperatureInFarenheit = (temperature * 9)/5 + 32
return(temperature)
}
//question is given below:
/*Let's add some code to the body of the function. Get rid of the existing return statement that's in
there and in this task we're going to write out code to take a Celcius temperature value passed in and
convert it to Fahrenheit.
To convert from Celcius to Fahrenheit - multiply the value by 9, divide the resulting value by 5 and then add 32.
Once you have the Fahrenheit value, return it from the function.*/
4 Answers
Jose Patarroyo
2,953 PointsAs you should have guess by now, the problem is that you are calling the function within itself, it doesn't work that way. The way to go is to declare a constant that will store the temperature in fahrenheit with the formula you have. Once it has the value stored, you should return that value. Hopefully what I just said makes sense to you.
Justin Bonaccorso
2,781 Pointsfunc temperatureInFahrenheit(temperature: Double) -> Double{
let celcius = (temperature * 9 / 5 + 32)
return celcius
}
It does get a bit confusing, but understanding that I needed to store the value for celcius and then return that same value, it clicked a bit better for me. Hopefully that helps.
Digvijay Jaiswal
5,565 PointsHi Justing,
your answer is correct, all i would add is we are calculating Fahrenheit here so rather than using celcius = blah blah we should use fahrenheit = blah blah. like below.
func temperatureInFahrenheit (temperature: Double) -> Double {
let fahrenheit = ((temperature * 9)/5) + 32
return fahrenheit
Tyron Spencer
1,489 PointsHi Digvijay Jaiswal Thankyou this has helped me also :)
Digvijay Jaiswal
5,565 PointsYou're welcome :)
Jose Patarroyo
2,953 PointsJose Patarroyo
2,953 PointsAs you should have guess by now, the problem is that you are calling the function within itself, it doesn't work that way. The way to go is to declare a constant that will store the temperature in fahrenheit with the formula you have. Once it has the value stored, you should return that value. Hopefully what I just said makes sense to you.