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Python Functional Python The Lambda Lambada Lambda

Posted by Ross Peace
Ross Peace
Courses Plus Student 17,401 Points

Lambda error

Use a lambda and filter() to create a variable named high_cal with only the items in meals where the "calories" value is greater than 1000.

meals.py 
meals = [
    {'name': 'cheeseburger',
     'calories': 750},
    {'name': 'cobb salad',
     'calories': 250},
    {'name': 'large pizza',
     'calories': 1500},
    {'name': 'burrito',
     'calories': 1050},
    {'name': 'stir fry',
     'calories': 625}
]

high_cal = filter(lambda item : item.calories > 1000 , meals)

2 Answers

Steven Parker
Steven Parker
229,785 Points
Steven Parker
Steven Parker
229,785 Points

You're really close. But your dict item has no calories attribute.

:point_right: Try indexing your item using the keyword name.

I'll bet you can get it now, but if you're still stuck...   <button' onclick='$("#spoiler").slideDown("slow");$(this).remove()'>Press to Reveal Spoiler</button> <div id='spoiler' style='display:none'>

:warning: SPOILER ALERT

high_cal = filter(lambda item : item['calories'] > 1000, meals)

</div>

Baitsheletse Thokwana
Baitsheletse Thokwana
4,136 Points
Baitsheletse Thokwana
Baitsheletse Thokwana
4,136 Points

this is how i solved the challenge

meals = [ {'name': 'cheeseburger', 'calories': 750}, {'name': 'cobb salad', 'calories': 250}, {'name': 'large pizza', 'calories': 1500}, {'name': 'burrito', 'calories': 1050}, {'name': 'stir fry', 'calories': 625} ]

high_cal = filter(lambda item : item['calories'] > 1000, meals)