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Java Java Basics Perfecting the Prototype Looping until the value passes

Dorka Tamas
Dorka Tamas
5,085 Points
Posted by Dorka Tamas
Dorka Tamas
5,085 Points

Last exercise, third question.

Hi,

I do not know where to put console.readLine... prompt. Can you help me please? :)

Thanks!

Example.java 
// I have initialized a java.io.Console for you. It is in a variable named console.
String response;
do {
  response  = console.readLine("Do you understand do while loops?  ");
  if(response.equalsIgnoreCase("No"));
} while(response.equalsIgnoreCase("No"));
if(response.equalsIgnoreCase("Yes")); {
  console.printf("Because you said %, you passed the test", response);
}

2 Answers

Kourosh Raeen
Kourosh Raeen
23,733 Points
Kourosh Raeen
Kourosh Raeen
23,733 Points

You forgot the s in %s. Also, there is not need for the if statement inside the loop. The loop condition is taking care of that. Also if you reach outside the loop it means the answer was yes so there is no need for an if statement there either:

// I have initialized a java.io.Console for you. It is in a variable named console.
String response;
do {
  response  = console.readLine("Do you understand do while loops?  ");
} while(response.equalsIgnoreCase("No"));
console.printf("Because you said %s, you passed the test!", response);
MacKenzie T. Stout
MacKenzie T. Stout
23,972 Points
MacKenzie T. Stout
MacKenzie T. Stout
23,972 Points

How is %s being used? Does it display the response from the console so long as it equals "No"?

Kourosh Raeen
Kourosh Raeen
23,733 Points
Kourosh Raeen
Kourosh Raeen
23,733 Points

You need the %s so that printf inserts the content of response there. Also, we use %s since response is a String. For an int variable you can use %d.

Dorka Tamas
Dorka Tamas
5,085 Points
Dorka Tamas
Dorka Tamas
5,085 Points

Thanks, now it is working! :)